Chemistry, asked by MrSANJAY2002, 1 year ago

Two gases A & B have critical temperature as 250 K and 125 K respectively. Which one of these can be liquified first and why?

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Answered by nikhil497146
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Answered by anjali1307sl
8

Answer:

The critical temperature of gas A is higher than gas B; thus, gas A liquified first.

Explanation:

Given data,

The critical temperature of gas A= 250K

The critical temperature of gas B = 125K

From the given gases, which gas liquified first =?

As we know,

  • The critical temperature is the maximum temperature at which the gas can be liquefied by pressure.

And,

  • Critical temperature \alpha the intermolecular force of attraction

Also,

  • The intermolecular force of attraction \alpha \frac{1}{liquification}

Therefore,

  • The higher the critical temperature, the higher the intermolecular force of attraction and, thus, easily the gas can be liquified.

Hence, the critical temperature of gas A is higher than gas B; thus, gas A liquified first.

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