Question

Two gases A and B having molecular masses 60 and 30 respectively are enclosed in a vessel.The weight of A is 1.2g and that of B is 6g. The partial pressure of A and B respectively if total pressure of mixture is 750mm of Hg ?

Answer 1

Answer:

Here in this question, we have to use the Dalton's law of partial pressure that states the given formula,

Partial pressure of gas A = Mole fraction of A * Total Pressure

Therefore, we have

Moles of A= 1.2/60 = 1/50

Moles of B = 6/30 = 1/5

Total moles = 11/50

Mole fraction of A = 1/11

Mole fraction of B = 10/11

Putting all these values in the above mentioned formula we get,

Pa = 1/11 * 750

Pb = 10/11*750

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