Question

Two gases a and b having same temperature t, same pressure p and same volume v are mixed. if the mixture is at the same temperature t and occupies a volume of v, the pressure of the mixture is what

Answer 1

At temperature constant, pressure is inversely proportional to volume. Therefore the mixture will exert pressure p corresponding to the amount of volume v occupied by the gases.

Answer 2

Answer:

2P

Explanation

Initially, according to ideal gas equation -

PV = nRT

As P, V & T are same for both gases, n must be same.

Later after mixing the two gases, V' = V & n' = n + n = 2n,

P'V' = n'RT

P'V = 2nRT

But nRT = PV,

P'V = 2(PV)

P' = 2P

Therefore, pressure of the mixture is 2P.