Question

Two gases h2 and o2 effuse from two different containers having same pressure and temperature. If the area of cross section of hole is 1:2 then the rate of effusion will be

Answer 1

Answer:

Let the rate of effusion of H2 be “r1” and of O2 be “r2”. Also, let the area of cross-section of hole for H2 be “A1” and for O2 be “A2”.

The ratio of A1 : A2 is given as = 1 : 2

The molecular mass of H2, M1 = 2 g/mol

The molecular mass of O2, M2 = 32 g/mol

We know that, when there is a small hole in the container with area of cross-section "A" , then  

The rate of effusion is = J(impingement) * A = [P*A*Na] / √[2πMRT] ….. (i)

From the above formula in (i), we can write

Rate of effusion ∝ [A / √M]

∴ r1/r2 = [A1/A2] * √[M2/M1]

⇒ r1/r2 = ½ * √[32/2]  

⇒ r1/r2 = 4/2 = 2 / 1

Thus, the ratio of the rate of effusion will be 2:1.

Answer 2

Answer:

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Explanation:

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