two gene A and B present on same chromosome show 40% crossing over then what will be the percentage of gamete (ab) in for the plant having genotype Aa b in cis arrangement..?
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There is 40% crossing over of A and B present on the same chromosome that means the probability of occurring of crossing over is 40/100 that is 0.4
Now if the cell has genotype AB/ab in cis arrangement then it has four types of gametes i.e AB, Ab, aB, ab. In which two gametes are of recombinant type and other is of parental type.
Considering aB as recombinant gamete of the plant having genotype Aa Bb is cis arrangement, therefore the probability of occurrence of aB is 1/2 i.e 50% or 0.5 Hence, the percent of gamete aB formed is 0.4 X 0.5 that is 2.0 So, the probability is 2.0 that is 20%.
sir can u again clear last paragraph.... plz
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after recommendation the cis type arrangement would be Aa and Bb
so the probability to finding these gametes would be 1/2
or 50%
but we have 40% recommendation genes so the total probability is .4 × .5
equals to 2.0 or 20%
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