Biology, asked by ishu3697, 3 months ago

Two genes R and Y are located very close on the
chromosomal linkage map of maize plant. When
RRYY and rryy genotypes are hybridized, the F2
segregation will show [AIPMT (Prelims)-2007]

(1) Higher number of the parental types.
(2) Higher number of the recombinant types.
(3) Segregation in the expected 9: 3: 3:1 ratio.
(4) Segregation in 3:1 ratio

help me plz

Answers

Answered by jayn24

Answer:

Option: (1) Higher number of the parental types.

Explanation:

When the two genes are closely related on the same chromosome, they get inherited together, and this phenomenon is known as Linkage, results in the increase in parental type progenies.

This concept can be well explained by the Morgan's observations after his experiment on Drosophila melanogaster. He observed:

When the two genes in a dihybrid cross are located on the same chromosome, the proportion of parental gene combinations in the progeny was much higher than the non-parental or recombination of genes.
When the genes are loosely linked, they show higher percentage of recombination.
Strength of linkage between genes is inversely proportional to the distance between them.

According to Morgan's observations, the F2 segregation will show higher number of the parental types.