Question

Two girls move in opposite directions, one from A to B and other from B to A. The girl from A reaches the destination in 16 hrs and girl from B reaches her destination in 25 hrs, after having met. If former's speed is 25 km/hr, what will be the speed of latter?​

Answer 1

The speed of the latter is 20 km/h

Step-by-step explanation:

Let the speed of the girl going from B to A be v km/hr

The distance between A to B = AB

Let the girl from A has travellevd distance = d before meeting the girl from B

According to the question

Girl from A takes 16 hours and girl from B takes 25 hours after they meet to reach their destination

Speed of girl from A = 25 km/hr

Using Distance = Speed × Time

$AB-d={25}\times{16}$

Again

$d=25\times v$

Dividing both we get

$\frac{AB-d}{d}=\frac{25\times 16}{25\times v}$

$\implies \frac{AB}{d}-1=\frac{16}{v}$   ....... (1)

If they meet after time t

Then in time t, the girl from A has travelled distance = d

And the girl from B has travelled distance = AB - d

Thus

$d=25\times t$

And $AB-d=v\times t$

From the above two equations

$\frac{AB-d}{d}=\frac{vt}{25t}$

$\implies \frac{AB}{d}-1=\frac{v}{25}$   ...... (2)

From equations (1) and (2)

$\frac{16}{v}=\frac{v}{25}$

$\implies v^2=16\times 25$

$\implies v=\sqrt{16\times 25}=4\times 5=20$ km/h

Therefore, the speed of girl from B is 20 km/h

Hope this answer is helpful.

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Answer 2

Answer:

Step-by-step explanation: X

speed 1 = 25 km/hr ; time 1 = 16 hr ; time 2 = 25 hr ;  Speed 2 = ?

As the distance for both will be same we will find distance from speed 1 and time 1 by formula :

S X T = D

25 X 16 = 400 KM

Now, finding Speed 2:

S = $\frac{D}{T}$

s = $\frac{400}{15}$

s = 16 km/ hr