Question

two glass capillary tubes one with radius r another one with radius 3r the heigt of the water rise in the tubes​

Answer 1

Answer:

ANSWER

h=

Rρg

(2Tcosθ)

Thus, h α

R

1

...............(1)

Now M=(πR

2

h)ρ

So, M α R

2

h .................(2)

So, combining equations 1 and 2,

M α R

So, doubling the radius will also double the mass of water will be doubble.

So, the mass of water =5g×2=10g

Answer 2

Answer:

5g*2=10g

hope you can understand