Question

Two glass plates enclose a wedge-shaped air film, touching at one edge and separated by a wire of 0.05 mm diameter at a distance of 0.15m from the edge. Calculate the fringe width. (wavelength =6000A)

Answer 1

Explanation:

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Answer 2

Answer:

The fringe width will be 9×10⁻⁴m.

Explanation:

The fringe width is given as,

$\beta=\frac{\lambda}{2\theta}$        (1)

Where,

β=fringe width

λ=wavelength of the light used

θ=angular separation between the glass plates

And the angular separation between the glass plates is given as,

$\theta=\frac{D}{d}$        (2)

D=diameter of the wire

d=distance from the edge

From the question we have,

D=0.05mm=0.05×10⁻³=5×10⁻⁵m

d=0.15

λ=6000A°=6000×10⁻¹⁰=6×10⁻⁷m

By substituting the value of D and d in equation (2) we get;

$\theta=\frac{5\times 10^-^5}{0.15}=0.33\times 10^-^3=3.3\times 10^-^4$     (3)

By substituting the value of θ and λ in equation (1) we get;

$\beta=\frac{6\times 10^-^7}{2\times 3.3\times 10^-^4}=0.90\times 10^-^3=9\times 10^-^4m$

Hence, the fringe width will be 9×10⁻⁴m.