Two glasses A and B contain a mixture of water and honey in the ratio 5:1 and 4:1 respectively. One-fourths of the mixture in glass A is poured out and refilled with the mixture from glass B. Find the ratio of water and honey in glass A.
Answers
Water in glass A = 5/6
Honey in glass A = 1/6
After pouring out ¼, remainder is 3/4
Remaining water in glass A = 3/4x5/6= 5/8
Remaining honey in glass A = 3/4x1/6 = 1/8
Water in glass B = 4/5
Honey in glass B = 1/5
Amounts added to glass A are ¼ of these values
Amount of water added = ¼ x 4/5 = 1/5
Amount of honey added = ¼ x 1/5 = 1/20
Total amount of water in A = 5/8 + 1/5 = 33/40
Total amount of honey in A = 1/8 + 1/20 = 7/40
Ratio of water : honey = 33/40 : 7:40
= 33 : 7
Answer:
Step-by-step explanation:
Water in glass A = 5/6
Honey in glass A = 1/6
After pouring out ¼, remainder is 3/4
Remaining water in glass A = 3/4x5/6= 5/8
Remaining honey in glass A = 3/4x1/6 = 1/8
Water in glass B = 4/5
Honey in glass B = 1/5
Amounts added to glass A are ¼ of these values
Amount of water added = ¼ x 4/5 = 1/5
Amount of honey added = ¼ x 1/5 = 1/20
Total amount of water in A = 5/8 + 1/5 = 33/40
Total amount of honey in A = 1/8 + 1/20 = 7/40
Ratio of water : honey = 33/40 : 7:40
= 33 : 7