Question

Two goods train each 500 m long, are running in opposite directions on parallel tracks. Their speeds are 45 km/hr and 30 km/hr respectively. Find the time taken by the slower train to pasś the driver of the faster one.??
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Answer 1

Given :

Two goods train each 500 m long, are running in opposite directions on parallel tracks. Their speeds are 45 km/hr and 30 km/hr respectively.

To find :

• The time taken by the slower train to pasś the driver of the faster one.

Solution :

★ Distance travelled by each goods train = 500m = length of each train

★ Speed of the first train = 45km/h

★ Speed of the second train = 30km/h

Let's find out relative speed of two train which are running in opposite directions

→ Speed of the first train + speed of the second train

→ (45 + 30)km/h

→ 75km/h

NOTE : If two train are running in same directions then we will use this formula,

• Relative Speed = speed of the first train - speed of the second train

Distance is given in 'meters' so let's convert speed km/h into m/s

→ 75 × 5/18 m/s

→ 125/6 m/s

The time taken by the slower train to pasś the driver of the faster one

${\boxed{ \bf Time = \dfrac{Distance \: travelled \: by \: slower \: train}{Relative \: speed}}}$

$\implies \sf t = \dfrac{ \dfrac{500}{125}}{6}$

$\implies \sf t = \cancel{500} \: ^{4}\times \dfrac{6}{ \cancel{125}}$

$\implies \sf t = 6 \times 4 = 24sec$

•°• The time taken by the slower train to pasś the driver of the faster one is 24 sec