Question

Two goods trains 150 m and 160 m long are
going in the same direction at 73 km per hour
and 42 km per hour, respectively. How long
would it take for them to pass each other if the
faster train is behind the slower train?​

Answer 1

Answer:

Step-by-step explanation:

Hence it is the train going at 73 km/hr which will pass the other by traversing a distance of (150+160) meters at a speed of (73-42) km/hr i.e. 310/1000 km at speed of 31 km/hr. Hence the answer is 1/100 th of an hour 3600/100 = 36 seconds.

Answer 2

Answer:

Solution : The relative speed of the trains = (73 - 42) km/hr

= 31 km/hr =

$31 \times \frac{5}{18} m \: per \: sec \:$

$= \: \frac{155}{18} m \: per \: sec \:$

Sum of the lengths of the trains = (150 + 160) m = 310