Question

Two grams sulphur is completely burnt in oxygen to form SO2.In this reaction.What is the volume (in litres) of oxygen consumed at S.T.P?(At.mass of S and O are 32 and 16 respectively.)

Answer 1

Since,

S + O2 -> SO2

2g of sulphur =2/32 mol=1/16mol

and atr. 1mol of S reacts completely with 1 mol O2

therefore, 1/16mol of S will react with 1/16 mol of O2

and we know 1 mol at STP= 22.4 L

1/16 mol= 22.4/16=1.4 L

Answer 2

Answer:

24gm

Explanation:

Atomic weight of Sulphur is 32 grams. Atomic weight of Oxygen is sixteen grams.

Molecular weight of SO2 is sixty four grams.

32 grams of Oxygen reacts with 32 grams of Sulphur to supply SO2

​1 gram of Oxygen will react with  32/32gram of Sulphur

Thus sixteen grams of Oxygen will react with sixteen grams of Sulphur to supply SO 2

​Now, this sixteen grams of Sulphur can be transformed to at least one mole of Sulphur Trioxide.

32 grams of Sulphur calls for forty eight grams of Oxygen to supply SO3

​

1 gram of Sulphur calls for  =forty eight/32 grams of Oxygen

Thus, sixteen grams of Sulphur would require 24 Grams of Oxygen (via way of means of unitery method).

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