Two grocery carts collide, a full one with a mass of 35 kg moving East at 2 m/s and an empty one with a mass of 10 kg moving West at 3 m/s. After the collision the full cart is moving East at 0.75 m/s. What is the velocity of the empty cart?
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Answered by
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HEYA!!!
HERE IS YOUR ANSWER,
>> GIVEN :
Mass (m₁) = 35 Kg. Mass (m₂) = 10 Kg, Initial Velocity (u₁) = 2 m/s, Initial Velocity (u₂) = -3 m/s and Final Velocity (v₁) = 0.75 m/s and Final Velocity (v₂) = ?
>> SOLUTION :
Applying Law Of Conservation of Momentum,
→ m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
→ (35 × 2) + (10 × -3) = (35 × 0.75) + 10v₂
→ v₂ = (70 - 30 - 26.3) ÷ 10
→ v₂ = 1.4 m/s (EAST)
>> THEREFORE,
Final velocity (v₂) = 1.4 m/s (EAST)
HOPE IT HELPS YOU,
THANK YOU.
HERE IS YOUR ANSWER,
>> GIVEN :
Mass (m₁) = 35 Kg. Mass (m₂) = 10 Kg, Initial Velocity (u₁) = 2 m/s, Initial Velocity (u₂) = -3 m/s and Final Velocity (v₁) = 0.75 m/s and Final Velocity (v₂) = ?
>> SOLUTION :
Applying Law Of Conservation of Momentum,
→ m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
→ (35 × 2) + (10 × -3) = (35 × 0.75) + 10v₂
→ v₂ = (70 - 30 - 26.3) ÷ 10
→ v₂ = 1.4 m/s (EAST)
>> THEREFORE,
Final velocity (v₂) = 1.4 m/s (EAST)
HOPE IT HELPS YOU,
THANK YOU.
Answered by
8
Solution:-
given ,
m1 = 35kg, u1=2m/s , m2= 10kg
u2 = -3m/s (opposit east side) , v1= 0.75m/s , v2= ?
by law of conservation of momentum
= m1u1+m2u2 = m1v1+m2v2
= 35×2+10×(-3 )= 35×0.75 +10v2
= 10v2 = 70-30-26.25
= v2 = 13.75/10 = 1.35 by round figure
= v2 = 1.4m/s (east) ans
given ,
m1 = 35kg, u1=2m/s , m2= 10kg
u2 = -3m/s (opposit east side) , v1= 0.75m/s , v2= ?
by law of conservation of momentum
= m1u1+m2u2 = m1v1+m2v2
= 35×2+10×(-3 )= 35×0.75 +10v2
= 10v2 = 70-30-26.25
= v2 = 13.75/10 = 1.35 by round figure
= v2 = 1.4m/s (east) ans
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