Question

Two guns are fired from the same place at an interval of 6 min. A person approaching the place observes that 5 min 52 second between the hearing of the sound of the two guns. If the velocity of the sound on 330m/sec, the man was approaching that place at the speed of (in kmph).

Answer 1

The answer to your question is : 27 km/h

Here is the solution:

Sound is the vibrations that travel from one medium to another,when they reach animal or humans ear they can be heard.the four basic properties of sound are timbre, dynamics, pitch and duration.

The difference of time will be :

t= 6 min-5 mins. 52 secs = 8 secs.

The distance covered by man in 5 mins and 52 secs is equal to the distance covered by the sound in 8 seconds .

distance= speed*time = 330*8 = 2640 m.

Hence, the speed of man it will be:

speed=distance/time= 2640/(5 min. 52 secs)

speed= 2640 m /352 secs

speed= 2640*18 /352*5

speed=27 km/h  .

Answer 2

Hey buddy,

◆ Answer- 7.5 m/s

◆ Explanation-
# Given-
v = 330 m/s
t = 6 min = 360 s
t' = 5 min 52 s = 352 s

# Solution-
Time difference is -
∆t = t' - t = 360 - 352 = 8 s

Here, we can say that,
Distance covered by by man in 352 s = Distance covered by sound in 8 s

Distance convered by man
D = 330 × 8
D = 2640 m

Speed of the man = Distance / time
v' = 2640 / 352
v' = 7.5 m/s

Speed of the man is 7.5 m/s.

Hope that helps...