Question

Two guns are pointed at each other, one upward at an angle
of elevation of 30°, and the other gun at the same angle of
depression. Both guns are kept 30 m apart. If the first gun
fires with 350 m/s and second gun with 300 m/s
simultancely. Find when do the two bullet meet. (Take g =
9.8 m/s) is :
(1) t= 1/65 s
(2) t = 2/65 s
(3) t= 3/65 s
(4) t= 4/65 s

Answer 1

Answer:

3/65 s is the answer of this question

Answer 2

Answer:

The correct option of this answer is

(3) 3/65

Step-by-step explanation:

Given:-  Angle of elevation for first gun= 30 degree

Angle of deviation for second gun= 30 degree

distance of the seperation between the both gun S re= 30m

velocity of the first gun = 350m/s

velocity of the second gun = 300m/s

combined velocity Urel = (300 + 350)m/s

                                        =650m/s

aslo acceleration due to gravity g = 9.8m/s

FORMULA USED:

t=Sre / Urel

CALCULATION:

ACCORDING TO FORMLA

t=(30/650) m/s

t=3/65m/s

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