Two hail stones with radii in the ratio of 1:4fall form a great height through the atmosphere then the ratio of their terminal velocitys is
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As the density of hailstones are same,
Mass of first = d× 34
πr
3
=M
Velocity of first =
9η
2r
2
(T
h
−T
a
)g
=V
For 2
nd
hail with radius =2r,
Mass of 2
nd
= d×
3
4
πr
3
2
3
=8M
Velocit of 2
nd
=
9η
2gr
2
(T
h
−T
a
)4
=4V
Ratio of Momenta =MV:8M×4V
MV:32MV=1:32
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