Question

Two half reactions with their positive oxidation potential are

Pb(s) – 2e- --->Pb2+ (aq) ; E° =+0.13V

Ag - e- ---> Ag+ (aq) ; E0

= -0.80V

Write the cell reaction and calculate the EMF.​

Answer 1

Explanation:

Hope u get it,

Btw, E° of cell = E° of RHE - E° of LHE