Question

two heater coils seperately take 10 min and 5 min to boil certain amount of water.if both the coils are connected in series,the time taken will be

Answer 1

Answer:

6min

Explanation:

Given that First heater boils certain amount of water in 15 minutes.

Another heater boils it in 10 minutes.

Let water boiled by both of them in one minute be 1 / x

Amount boiled by first heater in 1 minute = 1 / 15

Water boiled by another heater = 1 / 10

so the equation forms in this way :

1 / 15 + 1 / 10 = 1 / x

L.C.M = 30

1 × 2 / 15 × 2 + 3 × 1 / 10 × 3 = 1 / x

2 + 3 / 30 = 1 / x

5 / 30 = 1 / x

Cross multiply the fractions

5 × x = 1 × 30

5x = 30

x = 30 / 5

x = 6

So time taken by both the heaters to boil the water is 6 minutes.

So the answer is 6 minutes.

Hope it helps!!!!!!!!!!!!!