Question

Two heater wires of equal resistance are first connected in series and then in parallel. The ratio of the heats produced in the two cases is​

Answer 1

Answer:

In series the equivalent resistance is

R+R= 2R. Therefore,E1=I2(2R) t=2(I2Rt). In parallel the equivalent resistance =2RR2.

Therefore,E2=I2(2RR2) t=2I2Rt.

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Answer 2

n series the equivalent resistance is

R+R= 2R.

Therefore,

E1=I2(2R) t=2(I2Rt).

In parallel the equivalent resistance =2RR2.

Therefore,E2=I2(2RR2) t=2I2Rt.