Question

.Two heaters A and B each working with 230V for 5 minutes generates heat energy. Heater A has resistance 100 ohm and Heater B has resistance 1000 ohm.Which heater will generate more heat? ​

Answer 1

Answer :-

Heater 'A' will generate more heat than heater 'B' .

Explanation :-

For heater A :-

→ Potential difference = 230 V

→ Time = 5 mins = 300 sec

→ Resistance = 100 Ω

So, amount of heat generated :-

H = V²t/R

⇒ H = (230)² × 300/100

⇒ H = 52900 × 3

⇒ H = 158700 J

For heater B :-

→ Potential difference = 230 V

→ Time = 300 sec

→ Resistance = 1000 Ω

Amount of heat generated :-

H = V²t/R

⇒ H = (230)² × 300/1000

⇒ H = 52900 × 0.3

⇒ H = 15870 J

______________________________

Simply, 158700 J > 15870 J .

So, heater A generates more heat .

Answer 2

Given :-

Two heaters A and B each working with 230V for 5 minutes generates heat energy. Heater A has resistance 100 ohm and Heater B has resistance 1000 ohm.

To Find :-

Which heater will generate more heat? ​

Solution :-

We know that

I = V/R

For A

I = 230/100

I = 23 Ω

For B

I = 230/1000

I = 23/100

I = 0.23 Ω

Now

H = (I)² RT

For A

H = (23)² × 100 × 5 × 60

H = 529 × 100 × 300

H = 158700 J

For B

H = (I)² RT

H = (0.23)² × 1000 × 5 × 60

H = 0.0529 × 1000 × 300

H = 529/10000 × 100 × 300

H = 529 × 30

H = 15870 J

As A has more heat than B. Therefore, Heater A will generate more heat