Question

Two horizontal force of magnitude 10N and P N acts on a particle.The force of magnitude N acts due west and the force of magnitude P N acts on bearing of 30° east of north Find the magnitude of this resultant

Answer 1

Answer:

10√3N

Explanation:

Resultant acts along y-axis

Px = Pcos60∘ = 10N or P/2 =1 0 or P = 20

Resultant, Py = Psin60∘ = 20×√3/2 = 10√3N

Answer 2

Answer:

Explannswer:

2m/s

Explanation:

taking g as 10m/s

friction=un nswer:

2m/s

Explanation:

taking g as 10m/s

friction=un

=0.2* 1*10

2m/s

hope its helpful

=0.2* 1*10

2m/s

hope its helpfulation: