Question

two horizontal forces of 12n and 8n act on a body of mass 4kg. the minimum value of acceleration produced cannot be less than​

Answer 1

Given:

Two horizontal forces of 12N and 8N act on a body of mass 4kg.

To find:

Minimum acceleration of body ?

Calculation:

• Minimum acceleration can be found out by dividing the minimum force with the mass of the body.

• And the net force will be minimum, when the horizontal forces act in opposite directions to one another.

• Minimum force acting on the body = 12 - 8 = 4N.

$a_{min} = \dfrac{ f_{min} }{mass}$

$\implies a_{min} = \dfrac{ 4 }{4}$

$\implies a_{min} = 1 \: m {s}^{ - 2}$

The minimum acceleration produced in the body is 1 m/s².