Question

two horizontal pipes of different diameters are connected together by a valve. their diameters are 3 cm and 9 CM water flows at Speed 6 m/s in the first pipe and the pressure in it is 2 × 10^5 N/m². find the water pressure and speed in the second pipe?​

Answer 1

The water pressure and speed in the second pipe is 18 x 10^5 N/m^2  and 0.6 m/s

Explanation:

From the equation of continuity we can say that

A1V1 = A2V2

π (3)^2/6 x 6 = π(9)^2/6 x v

After cancellation:

v = 9 x 6 / 81 = 54/81 = 0.6 m/s

Now using Bernoulli equation.

P1 + ρV1^2/2 = P2+ ρV2^2/2

2 × 10^5  + 10^3 x 36/2 = P2 + 1/2 x 10^3 x 36

36 x 10^8 = P2 + 18 x 10^3

P2 = 36 x 10^8 - 18 x 10^3

P2 = 18 x 10^5 N/m^2

Learn more about Bernoulli equation

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Answer 2

Answer: Answer is in the attachment attached below.....