Two horizontal plates are placed 14 mm apart and the space between them is filled with an oil of viscosity 1.4 N-s/m2. If the upper plate moves with 2.5 m/s, the shear stress in the oil is
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Answer:
238
Explanation:
Dynamic viscosity of oil = 1.4 N-s/m²
Movement of upper plane = v = 2.5m/s
h = 14mm = 1.4cm
According to Newton’s law of viscosity -
τ∝du/ dy (rate of strain)
Thus, τ = μ.du/dy
where, μ is the proportionality constant
Thus, du/dy = vh =constant
=2.5/1.44×10−2
= 170
∴τ = 1.4 × 170
= 238
Thus the Shear stress between the oil layers is 238N/m²
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