Two horses start trotting towards each other, one from A to B and another from B to A. They cross each other after one hour and the first horse reaches B, 5/6 hour before the second horse reaches A. If the distance between A and B is 50 km. what is the speed of the slower horse?
A) 30 km/h
B) 15 km/h
C) 25 km/h
D) 20 km/h
Answers
Answered by
0
Answer:
a) 30 km/h is the correct answer
Answered by
0
Answer:
Step-by-step explanation:
Total distance = 50km
Speed of faster horse S1 = 50/{t-(5/6)}
Speed of slower horse S2= 50/t
As they cross each other in 1hr…
Total speed = S1 + S2
Now, T = D / S
50/(S1+S2) = 1
S1 + S2 = 50
50/{t-(5/6)} + 50/t = 50
t = 5/2, 1/3
t is not equal to 1/3 as 1/3 < 5/6, therefore t = 5/2
Put t= 5/2 in S2, it will give
S2 = 20km/hr
Similar questions