Two hot air balloons are flying above a park. One balloon started at a height of 3,000 feet above the ground and is decreasing in height at a rate of 40 feet per minute. The second balloon is rising at a rate of 50 feet per minute after beginning from a height of 1,200 feet above the ground. Given that h is the height of the balloons after m minutes, determine which system of equations represents this situation.
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A. h = 3,000 + 40m
h = 1,200 - 50m
B. h = 3,000m - 40
h = 1,200m + 50
C. h = 3,000 - 40m
h = 1,200 + 50m
D. m = 3,000 - 40h
m = 1,200 + 50h
h = 1,200 - 50m
B. h = 3,000m - 40
h = 1,200m + 50
C. h = 3,000 - 40m
h = 1,200 + 50m
D. m = 3,000 - 40h
m = 1,200 + 50h
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answer : D
Step-by-step explanation:
h=3000-40m
h=1200+50m
h means height and m means minutes
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