Question

two ice skaters initially at rest push each other.if one skater whose mass is 60kg has a velocity of 2m/s.find the velocity of other skater whose mass is 40kg

Answer 1

Hey User
Here is what You need
Due to absence of external Force, Momentum remains conserved i.e. P initial=P final
as P initial = 0 = P final
0 = 40×v + 60×2
v = -120/40 = -3m/s
hence man of 40kg mass move with velocity 3m/s in opposite direction as man of 60kg mass moves
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Answer 2

Hey!! Hi

Answer: −3ms^-1

Explanation:

Given,

Initial velocity, u1  =0 and u2 =0

Mass,m1 = 60kg and m2 = 40kg

Final Velocity,v1 = 2ms^−1

From conservation of momentum

Final momentum = initial momentum

m1v1 + m2v2 = m1u1 + m2u2

60 * 2 + 40v2 = 0

v2 = -3ms^−1

Hence, velocity of second skater is −3ms^-1

..THANK YOU..

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