Two ice skaters initially at rest, push off each other. If one skater whose mass is
60 kg has a velocity of 2 m/s, what is the velocity of other skater whose mass is
40 kg?
Answers
Answered by
2
Answer:
the answer is (60×2)÷40=3m/s.
Answered by
0
Answer:
Explanation:
We know
mu+mu=mv+mv
v=-120/40=-3
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