Question

Two identical bar magnets of magnetic moment M
each are inclined at 60° as shown in fig. The net magnetic moment of the combination in this position is ?​

Answer 1

Answer:

answer is root 3M

Explanation:

Answer 2

Answer:

The net magnetic moment of the given combination is $M\sqrt{3}$.

Explanation:

The net magnetic moment of the combination of magnets is given as,

$M=\sqrt{M^2_1+M^2_2+2M_1M_2cos\theta}$         (1)

Where,

M=net magnetic moment of the given configuration of the magnet

M₁=magnetic moment of the first magnet

M₂=magnetic moment of the second magnet

θ=angle between the given configuration of the magnet

From the question we have,

M₁=M₂=M

θ=60°

By substituting the required values in equation (1) we get;

$M_n_e_t=\sqrt{M^2+M^2+2M^2cos60\textdegree}$

$M_n_e_t=\sqrt{2M^2+2M^2\times \frac{1}{2} }$

$M_n_e_t=\sqrt{3M^2}$

$M_n_e_t=M\sqrt{3}$

Hence, the net magnetic moment of the given combination is $M\sqrt{3}$.