Two identical bottles A and B of sweet drinks contain sugar such that 30% of sugar in A is equal to 40% sugar in B. The ratio of sugar in the two bottles is
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Solution:-
Let the sweet drink in bottle A be 'x' and in the bottle B be 'y'.
So, according to the question 30 % of sugar of 'x' = 40 % of 'y'
30x/100 = 40y/100
x/y = 40/30
x/y = 4/3
4:3
The ratio of sugar in the two bottles is 4:3
Answer.
Let the sweet drink in bottle A be 'x' and in the bottle B be 'y'.
So, according to the question 30 % of sugar of 'x' = 40 % of 'y'
30x/100 = 40y/100
x/y = 40/30
x/y = 4/3
4:3
The ratio of sugar in the two bottles is 4:3
Answer.
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