Physics, asked by AnnieNair, 8 months ago

Two identical capacitors A and B are shown in figure. If a dielectric slab of dielectric constant K is slipped between the plates of capacitor B. Then energy of capacitor B will

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Answered by ReRepeater

2

Answer:

Explanation:

When dielectric slab is placed , energy will DECREASE

as we know E = 1/2CV²

where c is directly and v is inversely proportional to K

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