Question

Two identical capacitors are connected in parallel then switch is now open and filled with dielectrics

Answer 1

The question is not clear but still if this is the condition.

The potential difference in open switch becomes different while charges becomes constant.

So, if filled with dielectrics, you could just simply say from C=q/V, that V will become kV and hence by putting kV in C=q/V, the value of C will become C/k.

Please mark it as the brainliest.

Hope it helps