Question

Two identical capacitors each of capacitance 5uF are charged to potentials 2kV and 1kV respectively. Their -ve ends are connected together. When the +ve ends are also connected together, the loss of energy of the system is​

Answer 1

Answer:

1.25J

Explanation:

Given:

V1=2000V

V2=1000V

C=5uF

Formula Used:

Energy Loss = 1/2{(C1.C2)/(C1+C2)} (V1-V2)^2

Solution:

{(0.5*5*5*10^(-12))/10*10^(-10)}(1000)^2

1.25J