Physics, asked by ritikaguru2702, 12 days ago

Two identical capacitors 'P' and ' Q ' are connected as shown in figure. Now the switch is opened and a dielectric of dielectric constant '2' is introduced between the plates of a capacitor.The electrical energy after the introduction of the dielectric is (U = electrical energy initially)​

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Answered by shilpagoyal6567
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Answered by XxMissMavalixX
1

Explanation:

Two identical capacitors 'P' and ' Q ' are connected as shown in figure. Now the switch is opened and a dielectric of dielectric constant '2' is introduced between the plates of a capacitor.The electrical energy after the introduction of the dielectric is (U = electrical energy initially)

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