Question

two identical cells are connected in series and parallel then maximum power transfer to the load is​

Answer 1

Answer:

For what value of load resistance, the power transfer is maximum when two identical cells each of emf E and internal resistance r are connected (a) in series (b) in parallel. =E+E=2E. Note that in both the cases, maximum power deliverd to the loas is the same.

Answer 2

Given:

Two identical cells that are connected in series and parallel

To Find:

The maximum power transfer to the load

Solution:

The maximum power transferred to the load in series and the parallel combination is 2E²r and E²/2r respectively.

Let voltage of each cell be E and the internal resistance of each cell be r.

When cells are connected in series:

The equivalent voltage of the circuit = E + E = 2E

The equivalent resistance of the circuit = r + r = 2r

Hence the current in the circuit using Ohm's Law = 2E/2r

or I = E/r

Power transferred in series combination = I²(2r)

= $\frac{E^2}{r^2} X 2r$

= 2E²r    -  (1)

When cells are connected in parallel:

The equivalent voltage of the circuit = E X E / E + E = E / 2

The equivalent resistance of the circuit = r X r / r + r = r / 2

Power transferred in parallel combination = E²/2r      - (2)

So the power transfer is more in series combination than in parallel combination.