Two identical cells of negligible internal resistance, are connected in (A) series and in (B) parallel with each other. Find the ratio of currents through a load resistance R in the two cases
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Explanation:
Two identical cells of negligible internal resistance, are connected in (A) series and in (B) parallel with each other. Find the ratio of currents through a load resistance R in the two cases
Let each cell has Voltage = V
In series Voltage of cells be doubled = 2V
Current = 2V/R
in Parallel Voltage of cells would be = V
Current = V/R
Current in Series / Current in Parallel = (2V/R)/(V/R) = 2
the ratio of currents through a load resistance R in the two cases = 2
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