two identical charged spheres A and B when placed in air at some distance they repel each other with a force of 10^-5 N when 3rd uncharged sphere touched with A then with B and then placed exactly between A and B.
calculate net force on shphere C
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Answer: 3.75 ×10^-5 N.
Explanation:let the sphere A and B have charge q and distance between them r.
When C is brought in contact with A the charges distribute as q/2 each.
When C is brought in contact with B the charge distributed is 3q/4 each.
To get charge distribution you first add the charges of both spheres and then halved it.
So the net force on C is 3.74 ×10^-5 N.
Add both forces by A and B on C.
Hope this helps.
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