Two identical charges 3.0 m apart, exert forces of
magnitude of 90 newton on each other in vacuum.
The value of each charge is
(1) 3 x10-5 C
(2) 9 x10-8
(3) 3 x10-4C
(4) 9 x 10-3 C
Answers
Answered by
23
Hello Dear,
◆ Answer -
(3) q = 3×10^-4 C
● Explaination -
# Given -
F = 90 N
r = 3 m
# Solution -
Electrostatic force acting on point charges by each other is given by -
F = k.q1.q2/r²
F = k.q²/r²
q = r√(F/k)
q = 3 × √(90 / 9×10^9)
q = 3×10^-4 C
Therefore, the value of each charge is 3×10^-4 C.
Thanks dear.
Answered by
5
Answer:
Explanation:
F = 90 N
r = 3 m
# Solution -
Electrostatic force acting on point charges by each other is given by -
F = k.q1.q2/r²
F = k.q²/r²
q = r√(F/k)
q = 3 × √(90 / 9×10^9)
q = 3×10^-4 C
Therefore, the value of each charge is 3×10^-4 C.
Similar questions
Social Sciences,
5 months ago
Math,
10 months ago
Hindi,
10 months ago
Math,
1 year ago
Economy,
1 year ago