Question

Two identical charges 3.0 m apart, exert forces of
magnitude of 90 newton on each other in vacuum.
The value of each charge is
(1) 3 x10-5 C
(2) 9 x10-8
(3) 3 x10-4C
(4) 9 x 10-3 C​

Answer 1

Hello Dear,

◆ Answer -

(3) q = 3×10^-4 C

● Explaination -

# Given -

F = 90 N

r = 3 m

# Solution -

Electrostatic force acting on point charges by each other is given by -

F = k.q1.q2/r²

F = k.q²/r²

q = r√(F/k)

q = 3 × √(90 / 9×10^9)

q = 3×10^-4 C

Therefore, the value of each charge is 3×10^-4 C.

Thanks dear.

Answer 2

Answer:

Explanation:

F = 90 N

r = 3 m

# Solution -

Electrostatic force acting on point charges by each other is given by -

F = k.q1.q2/r²

F = k.q²/r²

q = r√(F/k)

q = 3 × √(90 / 9×10^9)

q = 3×10^-4 C

Therefore, the value of each charge is 3×10^-4 C.