Two identical charges of 2mmC are placed at points B(8cm,-2cm) and C(2cm,-2cm) respectively. Calculate the value of charge 'q' to be placed at a point A(a cm, 2cm) which is equidistant from the points B and C such that the electrostatics potential energy of a system is zero.
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Two charges of magnitude 5nC and −2nC, one placed at points (2cm,0,0) and (xcm,0,0) in a region of space, where there is no other external field. If the electrostatic potential energy of the system is −0.5μJ. The value of x
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Potential energy of system
U=4πε01rq1q2
0.5×10−6=(x−2)×10−29×109×5×10−9×(−2)×10−9⇒x=20cm
⇒ x=20cm
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