Question

Two identical concentric rings each of mass m and radius r are placed in a perpendicular to each other what is a moment of inertia about an axis passing through the centre of the mass of the system​

Answer 1

Answer:

a perpendicular to each other what is a moment of inertia about an axis passing through the centre of the mass of the system two identical concentric rings each pf mass m and radius r are placed in a perpendicular to eavh other .

Answer 2

Moment of inertia of ring $\dfrac{3}{2}mr^2$

Explanation:

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Given that

mass of the ring =m

radius = r

We know that ,mass moment of inertia of a ring axis passing through center

$I_1=m r^2$

mass moment of inertia of a ring axis passing through its diameter

$I_2=\dfrac{1}{2}mr^2$

The total mass moment inertia of the two rings

$I=I_1+I_2$

$I= m r^2+\dfrac{1}{2}mr^2$

$I=\dfrac{3}{2}mr^2$

Therefore the mass moment of inertia will be $\dfrac{3}{2}mr^2$