Physics, asked by KhushalK, 1 year ago

Two identical conducting rods are first connected independently to two vessels, one containing water
at 100°C and the other containing ice at 0° C. In the second case, the rods are joined end to end and
connected to the same vessels. Let q, and q, g/s be the rate of melting of ice in the two cases
respectively. The ratio q,/q, is
(JEE' 2004 (Scr.)]
ZA) 1/2
(B) 2/1
(C)41
(D) 114
0°C​

Answers

Answered by qwtiger
5

Answer:

I hope the options are like:

A) 1/2

(B) 2/1

(C)4/1

(D) 1/4

Two identical conducting rods are first connected independently to two vessels, one containing water

at 100°C and the other containing ice at 0° C

As we know,

Q/t=(θ1−θ2)/RÞ(Q/t)1=mL/t=q1/L  ...(i) Finally when rods are joined end to end

therefore putting the values  into equation (i)

=(100−0)/R/2  

 Þ (Q/t)2=mL/t=q2L=(100−0)/2R                   ... (ii)

From equation (i) and (ii),  

q1/q2=4/1

Hence option C will be the right answer.

Similar questions