Question

Two identical conductors of charge Q and Q/2 are brought in contact and again seperated. The charge on each conductor respectively is,​

Answer 1

Explanation:

Before touch the electrostatic force between them is F=

r

2

kq

1

q

2

When they are touched, the charge will flow still they have same potential. So the average charge on each sphere is q

a

=

2

q

1

+q

2

Thus, q

a

>q

1

and q

a

>q

2

So, after touch the force between them will be more than before.

hope it helps you buddy ✌️✌️

Answer 2

Answer:

Explanation: When the two are bought in contact the average of the two charges is distributed equally on both .

CHARGE ON EACH AFTER BRINGING THEM IN CONTACT=(Q+Q/2)/2=3Q/4

NOW THE ELECTROSTATIC FORCE BETWEEN THE TWO CAN BE CALCULATED EASILY USING F=K(3Q/4)(3Q/4)/R^2