Question

two identical copper spheres carrying charges + q and minus 9 Q separated by a certain distance has attractive force f if the spheres are allowed to touch each other and mode to distance of separation X so that the force between them becomes four f bi 9 then X is equals to​

Answer 1

Answer:

Two identical copper sphere carrying charges +Q and −9Q

Force between them =

q

4F

x= distance of separation x.

q

4F

=

4πϵ

0

1

x

2

Q×9Q

or, x

2

=

4F

9×10

9

×9Q

2

×9

∵ F being attractive force

or, x=d/2 equating this the solution will be held.