two identical cubes are placed adjoined in a row . find the ratio of their surface area of the the new keyword to that of the sum of the surface area of two cubes
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Dimensions of cube=a, a, a
Dimensions of cuboid = a, a, 2a
Surface area of cuboid =2(lb+bh+hl)
Scuboid=2(a2+2a2+2a2)=10a2
Scubes=6a2×2=12a2
ScubesScuboid=12a210a2=65.
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