Two identical cubes each of total surface area of 24 sq. cm are joined end – to – end. Which of the following is the total surface area of the cuboid so formed?
Answers
Answer:
48 sq.cm is total area of cuboid
Answer:
Total surface area of the cuboid = 40 cm³
Step-by-step explanation:
Given data
Two identical cubes each of total surface area of 24 sq cm are joined end to end
⇒ surface area of cube 6a² = 24 sq cm
a² = 4
side of the cube a = 2
now here we need to find total surface area of the obtained cuboid
when two identical cubes are joined together
the length of the cuboid will be double to the length of cube
and breadth and height are remains as same
dimensions of the cuboid are
length l = 2(2) = 4 cm
breadth (b) = 2 cm
height (h) = 2 cm
total surface area of the cuboid = 2[lb + bh + hl]
= 2[ 4(2) + 2(2) + 2(4)]
= 2 [ 8 + 4 + 8]
= 2 [ 20] = 40 cm³