Math, asked by mpumashankar, 3 months ago

Two identical cubes each of total surface area of 6 cm2 are joined end to end. Which of the following is the total surface area of the cuboid so formed? *

1 point

10 sq.cm

46 sq.cm

36 sq.cm

Answers

Answered by hkk1230
6

Answer:

6a^2=6

a=1

cuboid

l=2

b=1

h=1

TSA=2(2+1+2)

=2×5

=10

Answered by amitnrw
0

10 cm²  is the total surface area of cuboid formed by joining two identical cubes end to end each of  total surface area 6 cm²

Given : Two identical cubes each of total surface area 6 cm² are joined end to end .

To Find: the total surface area of the cuboid so formed

Solution:

Method  1 :

Two identical cubes each of total surface area 6 cm²

Hence total Surface area of both  = 6 + 6 = 12  cm²

A cube has 6 identical faces Hence,

Surface area of one face = 6/6 = 1 cm²

On joining two cubes end to end 1 face of each cube will be lost

Hence Surface area = 12 - 1 - 1 = 10 cm²

total surface area of the cuboid so formed = 10 cm²

Method  2:

Total Surface area of a cube = 6(Edge length)²

=> 6(Edge length)² =  6 cm²

=> Edge length = 1 cm

When two cubes joined together

Cuboid formed with length = 1 + 1 = 2 cm

Breadth and height  each 1 cm

Total Surface area of cuboid = 2 ( lb + bh + lh )

= 2( 2 * 1 + 1 * 1  + 2 * 1)

= 2 ( 2 + 1 + 2)

= 2(5)

= 10 cm²

10 cm²  is the total surface area of cuboid formed by joining two identical cubes end to end each of  total surface area 6 cm²

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