Two identical cubes each of total surface area of 6m² are joined end to end which of the following is the total surface area of the cuboid so formed ?
Answers
Answer:
Step-by-step explanation:
T.S.A of a cube = 6 m²
6a² = 6
a² = 6/6
= 1
side of the cube (a) = 1 m
cubiod
l =2 m
b = 1 m
h = 1 m
T.S.A of cubiod = 2( lb +bh +lh)
= 2( 2 + 1 + 2)
= 2(5)
= 10 m²
10 m² is the total surface area of cuboid formed by joining two identical cubes end to end each of total surface area 6 m²
Given : Two identical cubes each of total surface area 6 m² are joined end to end .
To Find: the total surface area of the cuboid so formed
Solution:
Method 1 :
Two identical cubes each of total surface area 6 m²
Hence total Surface area of both = 6 + 6 = 12 m²
A cube has 6 identical faces Hence,
Surface area of one face = 6/6 = 1 m²
On joining two cubes end to end 1 face of each cube will be lost
Hence Surface area = 12 - 1 - 1 = 10 cm²
total surface area of the cuboid so formed = 10 cm²
Method 2:
Total Surface area of a cube = 6(Edge length)²
=> 6(Edge length)² = 6 m²
=> Edge length = 1 m
When two cubes joined together
Cuboid formed with length = 1 + 1 = 2 m
Breadth and height each 1 m
Total Surface area of cuboid = 2 ( lb + bh + lh )
= 2( 2 * 1 + 1 * 1 + 2 * 1)
= 2 ( 2 + 1 + 2)
= 2(5)
= 10 m²
10 m² is the total surface area of cuboid formed by joining two identical cubes end to end each of total surface area 6 m²
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