Two identical cubes each of volume 64 cm^3 are joined together end to end. What is the surface area of the resulting cuboid?
Answers
Answered by
10
Answer:)
Volume of each cube=64cm^3
a^3= 64
a=4cm
Surface area of resulting cuboid=2(lb+bh+hl)
=2(8*4+4*4+4*8)
=2(32+16+32)
=2(80)
=160cm^2
Hence the surface area of resulting cuboid is 160cm^2
Answered by
3
Answer: 160cm².
Step by step explanation:
Given,
Volume of both cubes = 64cm³
Volume of one cube =a³
⇒ 64 = a³
⇒ (4) = a³
⇒ a=4
To find: We have to find the Surface area of resulting cuboids.
We know that, when two cubes are joined they form cuboid:
Length of cuboid=4+4= 8cm
Breadth of cuboid= 4cm
Height of cuboid= 4cm
Surface area of cuboid = 2(lb+bh+lh)
2(8×4+4×4+4×8)
= 2(32+16+32)
= 2(80)
= 160cm²
Therefore, Surface area of Cuboid is 160 cm².
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