Question

two identical cubical dice whose faces are numbered from 1 to 6 are rolled simultaneously twice . find the probability of getting a number whose sum is atleast 5​

Answer 1

Answer:

Two cubical dice whose faces are numbered 1 to 6 are rolled simultaneously once. The probability that the sum of the two numbers occurring on their top faces is more than 7 is 5/12.

Step-by-step explanation:

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Answer 2

Answer:

Two cubical dice whose faces are numbered 1 to 6 are rolled simultaneously once. The probabilitythat the sum of the two numbers occurring on their top faces is more than 7 is 5/12

Step-by-step explanation:

When two dices are rolled simultaneously

The total number of outcomes =6\times 6=36

The sum of the two numbers on the top of the faces will be more than 7 when the outcome is

(2,6),(3,6),(3,5),(4,6)(4,5),(4,4),(5,6),(5,5),(5,4),(5,3),(6,6),(6,5),(6,4),(6,3),(6,2)

Therefore, total number of favourable outcomes = 15

Therefore, the probability that the sum of the numbers if more than 7

= Number of favourable outcomes / Total number of outcomes

=

=5/12

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